4x^2-2x+1/4=0

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Solution for 4x^2-2x+1/4=0 equation: 



4x^2-2x+1/4=0

We multiply all the terms by the denominator


4x^2*4-2x*4+1=0

Wy multiply elements

16x^2-8x+1=0

a = 16; b = -8; c = +1;
Δ = b2-4ac
Δ = -82-4·16·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{8}{32}=1/4$

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